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Civil & Structural Engineering Cw · warping

Warping Constant Calculator

28 September 2026 9 min read

Warping constant Cw for I-sections (Cw = Iy·h²/4) with flange bending context.

Cw
964.54 ×10⁹mm⁶
warping
Iy
26.7
weak axis
J
1.27
torsion
h flange
H−tf
lever

Live statistics

Warping Cw

964.54 ×10⁹ mm⁶

Iy·h²/4

Iy flanges

26.72 ×10⁶mm⁴

weak-axis

J open

1.27 ×10⁶mm⁴

Σbt³/3

Use

LTB

Mcr ∝ √(GJe + ECw)

Schematic only — not to scale. Dimensions follow the inputs below.

Unit system
Flange width B(mm) Help
mm

One flange width.

Total depth H(mm) Help
mm

Overall depth.

Flange tf(mm) Help
mm

Flange thickness.

Web tw(mm) Help
mm

Web thickness.

Precision(decimals) Help
decimals

Decimals.

Precision
Results update live as you type

How you compare — standard sections

SectionDepth (mm)Mass (kg/m)A (cm²)Iₓ (×10⁶ mm⁴)Sₓ (×10³ mm³)
UB 305×165×40 · Steel I-beam 30440.351.385560
UB 457×191×67 · Steel I-beam 45467.185.52941290
UC 254×254×73 · Steel column 25473.193.1114895
RC 300×500 (C30) · Concrete beam 5003751500312512500
Glulam 140×450 · Timber beam 4502963010634725
SHS 200×200×8 · Hollow section 20047.460.436.9369

Indicative values for scheme design only. Always verify against the manufacturer / code tables (AISC Steel Manual, SCI Blue Book, ACI detailing) before ordering steel or pouring concrete.

Plans & details

Geometry

Section sketch

Dimensioned cross-section with centroid and axes. Verify b/h/t against drawings before issuing.

Detail

Bar layout / rolling

For RC: cover, bar positions and crack basis. For steel: rolling direction and weld access.

Nett

Connection zones

Holes, copes and welds deduct from gross — use nett properties at connections.

Typical details for scheme design. Replace placeholders with project drawings (1200×630 JPG or SVG line work in /public/plans/civil/). Do not scale from web images — use figured dimensions.

Design verification checklist

Work through before issuing results — 1/6 verified (17%).

Results

Normal

Warping constant

964.54×10⁹ mm⁶

Cw = Iy·(H−tf)²/4

Weak-axis inertia

26.72×10⁶ mm⁴

Flange-driven

Torsion constant

1.274×10⁶ mm⁴

Σbt³/3 open

Buckling use

Mcr

Mcr² ∝ EIy·GJ + E²Iy·Cw(π/L)²

Visualizations

Warping constant (×10⁹ mm⁶)

964.5 ×10⁹ mm⁶Cw

Formula

Flanges bend laterally in opposite directions under twist; their differential bending (Iy) times the lever h squared over 4 is the warping resistance.

Cw = Iy·h²/4, h = H − tf | Iy = (2tf·B³ + hw·tw³)/12 | J = Σbt³/3

Alternative Form

Mcr ≈ (π/Lb)·√(EIy·GJ + (πE/Lb)²·Iy·Cw) — Cw rules long unbraced beams

Variables

SymbolNameUnitDescription
CwWarping constantmm⁶Restrained-twist geometry.
IyWeak inertiamm⁴Flange lateral bending.
hFlange levermmH − tf between centroids.
JTorsionmm⁴St Venant companion.

Explanation

Cw = Iy·h²/4: flange lateral bending times lever squared — warping stiffness that rescues long beams GJ alone cannot.

Derivation

Differential flange shear from unit twist-rate gradient integrates to flange moments; virtual work gives Cw = Iy·h²/4 for doubly-symmetric I (Vlasov).

Step-by-Step Calculation

Follow each step to understand how the result is calculated from your inputs.

Step 1

Enter flange B × tf, depth H, web tw

Result: I fixed
Step 2

Read weak-axis Iy

Result: Lateral bending
Step 3

Read Cw = Iy·h²/4

Result: Warping issued
Step 4

Read companion J

Result: Torsion paired
Step 5

Feed both into LTB Mcr

Result: Buckling linked
Step 6

Brace to cut Lb if short

Result: Bracing queued
Final Answer
964.54

Worked Examples

See how the calculator works with different scenarios.

Scenario

Warping screen.

Inputs

B:200 mm
H:400 mm

Calculation

Iy = (40·8e6 + 360·1728)/12 = 27.2e6 mm⁴. h = 380. Cw = 27.2e6·144400/4 = 9.82e11 = 982 ×10⁹ mm⁶.

Result

Cw ≈ 982 ×10⁹ mm⁶

Interpretation

Long unbraced spans lean on this number — brace to cut Lb² dependence.

Understanding Your Result

Your Result: Warping constant = 964.54 ×10⁹ mm⁶ · Weak-axis inertia = 26.72 ×10⁶ mm⁴ · Torsion constant = 1.274 ×10⁶ mm⁴

Typical range: UB-scale I: Cw hundreds to thousands ×10⁹ mm⁶; wide flanges multiply by B³.

What This Means

Warping stiffness geometry with Iy and J companions — the LTB inputs for unbraced I-beams.

Why It Matters

Unbraced beams fail sideways-twisty, not in-plane. Cw (with J and Iy) sets the real Mcr designers claim.

Professional Interpretation

Quote Cw with Lb and Cb in the LTB check (AISC 360 Ch. F). Brace the compression flange first; steel second.

Recommendations

  • •Verify dimensions against the drawing before issuing properties
  • •Use gross properties for analysis; cracked/nett for checks as codes require
  • •Compare required S/I against the standard-section table below

Learn — structural behaviour, deeply

Twist restrained is twist resisted twice.

1 · The two equations that run every site

ΣF_y = 0

Vertical balance

Upward reactions must equal total downward load. Missing 1 kN here means a 1 kN shear error everywhere downstream.

ΣM = 0

Moment balance

Moments about ANY point must cancel. Take moments about one support to eliminate it and solve the other directly.

ΣF_x = 0

Horizontal balance

Zero for vertical-only loading — but the pin still needs checking once wind, soil or inclined loads appear.

Worked derivation (simply supported, point load): ΣMleft = 0 ⇒ Rb·L − P·a = 0 ⇒ Rb = P·a/L, then ΣFy = 0 ⇒ Ra = P − Rb = P·(L−a)/L. UDL adds w·L/2 per side acting at midspan. That is the entire calculation — everything else is bookkeeping.

2 · Support types — what each one can (and cannot) do

SupportReactionsAllowsWatch out
Roller1 (vertical)Horizontal slide + rotationProvides NO lateral restraint — pair with a pin or bracing.
Pin / hinge2 (vertical + horizontal)Rotation onlyMoment released here — detail the hinge, never weld it rigid by accident.
Fixed / clamped3 (+ moment)Nothing (fully restrained)Attracts large moments; settlement or temperature causes locked-in stress.
Propped cantilever3 (indeterminate ×1)Rotation at propNeeds compatibility (deflection = 0 at prop) — equilibrium alone is not enough.
Continuous (3+ supports)4+ (indeterminate)Rotation over interior piersSolve by superposition / moment distribution / software; reactions shift with stiffness.

3 · Factor-impact table — what moves your reactions most

FactorTypical impactWhy
Load position (a/L)Linear, dominantMoving P toward a support shifts ~100% of P onto it. Ra = P·(L−a)/L — position matters more than span.
UDL intensity (w)∝ w·L totalEach extra 1 kN/m on a 6 m beam adds 3 kN per reaction. Self-weight alone is often 1–5 kN/m on concrete.
Span length (L)∝ L for UDLDoubling L doubles UDL reactions and quadruples UDL moment (wL²/8). Keep spans tight where possible.
Overhang length (c)∝ c/L upliftUplift at the far support = P·c/L. A 2 m overhang with 10 kN on a 5 m span pulls down 4 kN — needs hold-down.
Fixity (pinned → fixed)Redistributes ~10–30%Fixed ends attract moment and shed midspan moment. Never assume fixity you have not detailed.
Support settlement (Δ)0 (det.) / large (indet.)Determinate beams just rotate; continuous/fixed beams develop locked-in moments ≈ 3EIΔ/L².
Dynamic / impact+10–100%Static reactions must be amplified for cranes, machinery, footfall (see ASCE 7 Ch. 4, AISC DG11).
Load combination× 1.2–1.6 (LRFD)1.2D + 1.6L + 0.5(Lr/S/R) governs most beams. Reactions for strength ≠ reactions for service checks.

4 · Code provisions you must cite on drawings

  • ASCE 7 load combinations (LRFD): 1.4D · 1.2D + 1.6L + 0.5(Lr/S/R) · 1.2D + 1.0W + 1.0L … Strength reactions use factored loads; bearing/deflection checks use service (unfactored) loads.
  • ACI 318 (concrete): strength-reduction ϕ = 0.65–0.90; development/lap lengths Ch. 25; one-way shear + punching Ch. 22. Reactions feed directly into Vu ≤ ϕVn.
  • AISC 360 (steel): Ch. F/G/H for moment/shear/combined; bearing at supports per J7–J8; bracing per App. 6. Connection must develop the computed reaction — a beam is only as strong as its seat.
  • Eurocode basis (EN 1990): ULS 1.35G + 1.5Q; SLS G + Q (characteristic). National annexes adjust factors — confirm the project annex.
  • Serviceability (all codes): live-load deflection ≈ L/360 floors, L/240 roofs; total ≈ L/240. Vibration: AISC DG11 / SCI P354 for rhythmic or office floors.

5 · Pro workflow (5 minutes per beam)

  1. Sketch the free-body diagram: every load incl. self-weight, every support, dimensions.
  2. Solve ΣM then ΣF — write both lines on the calc sheet so a checker can follow.
  3. Verify: re-take moments about the OTHER support; residual must be ≈ 0.
  4. Draw shear then moment (reactions are the SFD starting values).
  5. Size the support: bearing stress, padstone, bolt/weld group, foundation pressure.
  6. File: keep the input → reaction → SFD/BMD → support chain on one page.

6 · Field traps (where reactions go wrong)

  • • Forgetting self-weight: a 300×600 concrete beam weighs 4.5 kN/m — on 6 m that is 13.5 kN per support.
  • • Assuming fixity: a “fixed” sketch with two bolts is a pin. Model what you detail.
  • • Ignoring uplift: overhang + wind can reverse a bearing — light roofs lift off.
  • • Mixing factored/service: never compare a factored reaction against an allowable soil pressure.
  • • Point load at the wrong station: 0.5 m error on a 10 kN load swings reactions by P·Δa/L.

7 · The 3-check rule (sign-off standard)

  1. Math check: ΣFy and ΣM both close to zero with project units printed.
  2. Sanity check: reactions sum to total load; heavier side sits under heavier load; UDL symmetry gives Ra ≈ Rb.
  3. Load-path check: every reaction lands on something sized for it — beam → seat → column → footing → soil, no floating numbers.

Practical Tips

  • •Depth beats width: I ∝ h³, S ∝ h², A ∝ h — deepen before widening
  • •State the basis: gross, nett, cracked or transformed
  • •Cross-check S_req = M/σ against the table below

Common Mistakes

Mixing mm and cm in one calc
Enter all dims in the selected unit; the solver converts once internally.
Using gross I for RC deflection
Use cracked Ie plus creep for service deflection.
Ignoring fillets then ordering tight
Fillets add 1–3%: fine for scheme, verify against mill tables for order.

Assumptions

This calculator makes the following assumptions to provide estimates:

Sharp-corner idealisation: Fillets, welds and chamfers ignored (1–3% on area, less on I for scheme).
Prismatic section: Properties constant along the member length.
Homogeneous elastic material: Single E unless a modular ratio n is entered.

Limitations

Be aware of these limitations when using this calculator:

Gross elastic properties: Nett (holes) and cracked/transformed variants need their own deductions.
Thin-wall torsion approx.: Open-section J ≈ Σbt³/3; warping Cw per standard approximations.

Frequently Asked Questions

Answers to common questions about this calculator.

What is warping?
Twist with ends restrained forces flanges to bend laterally opposite ways — extra stiffness beyond St Venant GJ, priced by E·Cw.
When does Cw matter?
Long unbraced I-beams in bending (LTB): Mcr blends GJ (short) and E·Cw/L² (long). Short braced beams barely feel it.
Units of Cw?
Length⁶: mm⁶ (reported ×10⁹) or in⁶. Pairs with E (force/length²) to give force·length⁴.
Channels and angles?
Different Cw forms (shear-centre offsets). This page is doubly-symmetric I; use section tables for channels/angles.
How do I raise Cw?
Widen flanges (B³) or deepen (h²). Bracing (shorter Lb) usually beats steel weight.
Box sections?
Closed boxes barely warp (huge J dominates). Cw checks are an open-section game.
What is section modulus and how do I use it?
S = I/c (mm³): the geometric bending efficiency of a section. Bending stress = M/S; required S = factored moment / allowable (or design) stress. Compare against the standard-section table on each page.
How do I quickly check a steel beam?
Three checks per AISC 360: bending (Ch. F incl. lateral-torsional buckling over the unbraced length), shear (Ch. G), and deflection (L/360). Then verify the connection develops the end reaction.
How do I quickly check a concrete beam?
Flexure per ACI 318: ϕMn = ϕ·As·fy·(d − a/2) with ϕ = 0.9 (tension-controlled); one-way shear Vc + Vs (Ch. 22); deflection via minimum thickness or direct computation with cracked stiffness and long-term multiplier.
Shear vs bending moment — which sizes what?
Shear sizes stirrups/webs and connections (V ≤ ϕVn); bending moment sizes flexural steel and the section (M ≤ ϕMn via section modulus S: stress = M/S). Deflection is governed by stiffness EI, a third independent check.
Where does the maximum moment occur?
Where shear crosses zero: under a midspan point load, or at x = R/w under UDL (span moment = R·x − w·x²/2). On continuous beams also check the hogging peaks OVER interior supports — they often govern.
How do I convert kN ↔ kips and m ↔ ft?
1 kN = 0.2248 kips (1 kip = 4.448 kN); 1 m = 3.2808 ft. Moments: 1 kN·m = 0.7376 kip·ft. Every calculator on this site has an SI/Imperial toggle that converts all displayed values.
Which codes do these calculators follow?
Workflows cite ACI 318 (concrete), AISC 360 (steel), ASCE 7 (loads + combinations), IBC (deflection, occupancy loads) and Eurocode equivalents. Always confirm the edition and annex your project is permitted under.
How accurate are these calculators?
Scheme-stage accuracy from closed-form statics with stated assumptions (rigid supports, prismatic sections, static loads). Use them for sizing, checking and tender estimates — final permit/shop drawings need a licensed engineer and project-specific analysis.
Can I print, copy or share results?
Yes — every page has print, copy-link and share actions in the hero banner, and results render in a printable dashboard. Paste the equilibrium line (ΣR vs total load) onto your calc sheet as the proof.
Do I still need a structural engineer?
For anything that gets built: yes. Software and calculators don’t carry liability, don’t visit site, and don’t know your soil, wind exposure or buildability constraints. Use these tools to brief and check your engineer, not replace them.
What is development length and why does it matter?
The embedment needed for a bar to reach yield (ld, ACI 318 Ch. 25). A perfectly computed moment capacity is worthless if the bar pulls out — extend bars past inflection points and hook or develop them at supports.
How do I check bearing stress under a support?
Bearing stress = reaction / (bearing length × width) ≤ allowable (masonry ≈ 0.25–0.4·f′m, concrete per ACI 22.8, steel per AISC J8). If it fails, lengthen the bearing or add a padstone/spreader plate.
What deflection limits apply to beams?
Typical code limits: live-load deflection L/360 for floors (L/240 roofs), total-load L/240, cantilevers 2L/360-ish per IBC Table 1604.3. Always check under SERVICE loads with the correct (cracked, long-term) stiffness.
LRFD vs ASD — does it change the reactions?
No — equilibrium is the same. The design PHILOSOPHY differs: LRFD factors loads up (1.2D+1.6L) against factored resistance (ϕRn); ASD keeps service loads against allowable stresses (Rn/Ω). Keep the two systems in separate columns.
Which load combination usually governs a beam?
For strength: 1.2D + 1.6L (+ 0.5 for roof live/snow/rain) per ASCE 7 LRFD. Service D+L governs deflection and bearings; 0.9D + 1.0W governs uplift and overturning.
Service vs factored loads — which do I report?
Report BOTH in separate columns: service (unfactored D+L) for deflection, bearing, settlement and soil checks; factored LRFD (1.2D + 1.6L) for member strength. Never compare a factored reaction with an allowable soil pressure.
Pin, roller or fixed — how do I choose the support model?
Model what you DETAIL. Masonry/steel seats and two-bolt end plates are pins (moment released); moment frames, welded rigid joints and well-anchored cantilevers earn fixity. When in doubt, the pinned assumption is conservative for midspan moment but NOT for uplift.
Hold-down or bigger pad — which fixes uplift?
Only a hold-down (strap, anchor, dead weight) fixes uplift — a bigger pad just spreads a force acting the wrong way. Size the anchor for net factored uplift (0.9D + 1.0W) with proper embedment.
How does wind create uplift on beams and roofs?
Suction on leeward slopes/overhangs pulls upward; the net combination 0.9D + 1.0W (ASCE 7) often reverses light end reactions. Run it explicitly — gravity-only models hide the governing hold-down case.
How do I allow for impact and vibration?
Amplify static reactions per ASCE 7 Ch. 4 (cranes, machinery, forklifts: +10–100%) and check footfall vibration with AISC DG11/SCI P354 on office, gym and lab floors. These calculators report static values — apply the factors yourself.
How do I find reactions for a simply supported beam?
Take moments about the left support: Rb = (P·a + w·L·L/2) / L, then Ra = P + w·L − Rb. Always re-check by taking moments about the right support — the residual must be ≈ 0.
What does a negative (downward) reaction mean?
The support must pull DOWN instead of pushing up — net uplift from overhangs, pattern loading or wind. Provide a hold-down strap, anchor or ballast; a gravity-only bearing will lift off.
Do I include the beam self-weight?
Yes, always. A 300×600 mm concrete beam weighs ~4.5 kN/m — on a 6 m span that adds ~13.5 kN per support. Bundle it into the UDL before solving.
What is the difference between a UDL and a UVL?
A UDL (uniformly distributed load) is constant intensity over a length (kN/m). A UVL (uniformly varying / triangular) runs zero-to-max — e.g. soil or hydrostatic pressure. They integrate differently, so use the matching calculator.
How do I turn a floor area load into a beam line load?
Multiply the area load (kN/m²) by the tributary width (m) draining to the beam: line load = area load × tributary width. Add the beam self-weight, partitions and finishes first.

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Glossary

Technical terms used in mortgage calculations explained in plain language.

Reaction
Force (or moment) a support exerts on a member to maintain static equilibrium (ΣF = 0, ΣM = 0).
Simply supported
Beam on one pin + one roller. Resists vertical load; allows rotation and (at roller) horizontal movement.
Fixed support
Clamped end resisting force AND moment; prevents rotation. Used in cantilevers and fixed frames.
UDL / UVL
Uniformly distributed load (constant kN/m) vs. uniformly varying load (triangular, zero-to-max).
Tributary area
Floor/roof area whose load drains to one member. Line load = area load × tributary width.
Factored load
Service load × LRFD load factor (e.g. 1.2D + 1.6L) for strength design per ASCE 7.
Serviceability
Deflection, cracking and vibration limits under day-to-day (unfactored) loads.
Uplift
Net downward-hold requirement: a negative (downward-pulling) reaction, common on overhangs.

Authoritative References

Trusted sources and standards referenced by this calculator.

Applicable Standards

ACI 318 — Building Code Requirements for Structural ConcreteAISC 360 — Specification for Structural Steel BuildingsASCE 7 — Minimum Design Loads and Associated CriteriaEurocode 2 (EN 1992) — Design of Concrete StructuresEurocode 3 (EN 1993) — Design of Steel StructuresIBC — International Building Code (structural chapters 16–23)

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Last Updated:

2026-09-28

Version:

2.0.0

License:

Free to use for educational and professional purposes.